Real Easy PHP/Java Query

[BLazeD]

I have a site, eg www.house.com

I want one ad to show on every single page, except any page that has www.house.com/forum* in the URL.

For the pages that have www.house.com/forum* in the URL I want to show another ad.

I guess either javascript or PHP could do this.

eg.

Define URL

IF URL=www.house.com/forum*

Then

Display AD2

ELSE

Display AD1

I know how it should work, just not the actual code.

Help much appreciated!!!!

PS: Any questions about what I have said please ask, I really need this help

[Bender]

<script type="text/javascript">
//****************configuration **********************//
//string to look for 
lookFor="www.house.com/forum";

//HTML to display when the string was NOT found -take care of the proper quotes embedding-
// do not add single quotes without addin a \ first
HTML1='<img src="http://www.mysolarsystem.com/images/jupiter.jpg">';

//HTML to display when the string was  found
HTML2='<img src="http://www.mysolarsystem.com/images/saturn.jpg">';

//****************configuration ends here  **********************//
w=location.href;

index=w.indexOf(lookFor);
if(index=-1){
//the current URL does not contain searched string
document.write(HTML1);
}
else{
//the current URL contains the searched string
document.write(HTML2);
}

</script>

I hope this helps.
PS:
Java and javascript are extremely different...

[BLazeD]

Cheers man,

I dont think it is working though, because the ads themselves are java and I dont know how to edit them to be compatible with the above.

Some other guy suggested

<? if (eregi('www.house.com/forum', $_SERVER['HTTP_HOST'].'/'.$_SERVER['PHP_SELF'])) { ?>
Display AD2
<? } else { ?>
Display AD1
<? } ?>

But it only displays AD1, even when AD2 is meant to be displayed.

[Bender]

If you prefer PHP,here is the code.
The JavaScript(not Java!) method works as well, both tested.

<?
$lookFor="www.house.com/forum";
$url = $HTTP_SERVER_VARS["HTTP_HOST"] . $HTTP_SERVER_VARS["REQUEST_URI"];
 if (eregi($lookFor, $url)) { ?> 
Display AD2 
<? } else { ?> 
Display AD1 
<? } ?>

[BLazeD]

Awesome

I have it going now - thanks a lot!

[Mr.Domains]

The JavaScript(not Java!) method works as well, both tested.

Lol, I get this all the time! In fact, last birthday my wife even gave me a great big "Programming Java Applets" manual, and then was quite affronted when I tried to explain to her that I don't use Java and had no interest in learning how too. - "But you did that JavaScript course last summer and said it had been really useful to you?"

[BLazeD]

Any idea how to change the PHP version of this code, to include multiple URLs?

ie. abc.com/a.php and abc.com/b.php it doesnt display

But for any other abc.com address it will display?

Cheers

[csmaster2005]

all you'd have to do is change the $lookfor variable.
basically what the script is doing is just checking what the url that is being requested is, then compares the url against the lookfor variable, and does a simple if else statement.
easy to modify for any site.

[unknowngiver]

can u explain the code pleasE?
i m a newbie {learning php} and would like to know wt this code means

<?
$lookFor="www.house.com/forum";
$url = $HTTP_SERVER_VARS["HTTP_HOST"] . $HTTP_SERVER_VARS["REQUEST_URI"];
if (eregi($lookFor, $url)) { ?>
Display AD2
<? } else { ?>
Display AD1
<? } ?>